Lösung zu Pumpspeicherwerk

1. [math]\displaystyle{ \eta_{Turbine} = \frac {P_{elektr}}{P_{hydr}} = \frac {P_{elektr}}{\rho g \Delta h I_V} }[/math]= 0.943 (94.3%)
2. [math]\displaystyle{ \eta_{Pumpe} = \frac {P_{hydr}}{P_{elektr}} }[/math] [math]\displaystyle{ P_{elektr} = \frac{P_{hydr}}{\eta} = \frac{\rho g \Delta h I_V}{\eta} }[/math] = 333 MW
3. 1-η² = 0.111 oder 11.1% Verlust

Aufgabe